How do you write the equation #y=2/3x+1# in standard form and identify A, B, C?

1 Answer
Jim G.
Sep 9, 2017

#2x-3y=-3#

Explanation:

#"the equation of a line in "color(blue)"standard form"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(Ax+By=C)color(white)(2/2)|)))#
where A is a positive integer and B, C are integers.

#"rearrange "y=2/3x+1" into this form"#

#"multiply through by 3 to eliminate the fraction"#

#rArr3y=2x+3#

#"subtract 3y from both sides"#

#cancel(3y)cancel(-3y)=2x-3y+3#

#rArr0=2x-3y+3#

#"subtract 3 from both sides"#

#0-3=2x-3ycancel(+3)cancel(-3)#

#rArr2x-3y=-3larrcolor(red)" in standard form"#

#rArrA=2, B=-3" and "C=-3#

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