How do you write the equation #y= -2(x+1)^2+3# in standard form?

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Answer 1 · 2016-12-14T21:37:26

Since we're dealing with a quadratic, the standard form will look like:

#Ax^2+Bx+C=0#

Thus, we must expand the function and organize as such:

#y=-2(x+1)^2+3#

#-2(x^2+2x+1)+3=0#

Distribute and simplify:

#-2x^2-4x+1=0#