# How do you write the equation y=(x-2)^2+ 6 in standard form?

Just multiply out the square of the binomial (with "FOIL") and then combine like-terms to get $y = {x}^{2} - 4 x + 10$.
Using "FOIL" (First-Outside-Inside-Last) gives ${\left(x - 2\right)}^{2} = \left(x - 2\right) \cdot \left(x - 2\right) = {x}^{2} - 4 x + 4$.
Therefore, $y = {\left(x - 2\right)}^{2} + 6 = {x}^{2} - 4 x + 4 + 6 = {x}^{2} - 4 x + 10$. This is "standard form".