# How do you write the equation y= (x-4)(x-2) in standard form?

Apr 11, 2018

$y = {x}^{2} - 6 x + 8$
$\left(x - 4\right) \left(x - 2\right) = x \cdot x - 2 \cdot x - 4 \cdot x + 8 =$
$= {x}^{2} - \left(2 + 4\right) x + 8 =$
$= {x}^{2} - 6 x + 8$