# How do you write the explicit formula for the sequence 2,8,32,128,...?

Mar 11, 2016

${2}^{2 n - 1}$
${2}^{1} , {2}^{3} , {2}^{5} , {2}^{7.} \ldots \ldots \ldots . .$
Here the power of 2 is in AP whose first term =1 and common difference is 2, so nth term will be$1 + \left(n - 1\right) \times 2 = 2 n - 1$
Hence nth term of given series is ${2}^{2 n - 1}$