How do you write the exponential notation for #log_y 27 = 3#?

2 Answers
Nov 11, 2015

#y^3=27#

You did not request that the value for y be determined. Only how the notation be represented.

Nov 11, 2015

Use the definition of log:

Explanation:

You take the base #y# and "push" up the #3# getting rid of the log to get:
#27=y^3#
where you can see that #y=3# because #3^3=27#.