How do you write the expression #(x+6)(x-2)# as a polynomial in standard form?

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Answer 1 · 2016-03-21T15:57:30

The final answer: #x^2 + 4x - 12#

To write the expression #(x + 6) (x - 2)# in standard form you can FOIL (First Outer Inner Last).

#x xx x = x^2#

#x xx (-2) = -2x#

#6 xx x = 6x#

#6 xx (-2) = -12#

After foiling completely you get:

#x^2 - 2x + 6x -12#

Next, you combine like terms.

#-2x + 6x = 4x#

There are no other like terms. Therefore, your final answer is

#x^2 + 4x - 12#

Answer 2 · 2016-03-21T23:12:48

It's really a lot easier to see the FOIL method than explain.

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Then, once foiled out, combine like terms.
Your final answer will be, x^2 +4x -12