How do you write the first five terms of the geometric sequence $a_{1} = 3, r = \sqrt{5}$ $a_1=3, r=sqrt5$ ?

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Answer 1 · 2017-09-04T19:19:56

${3, 3 \sqrt{5}, 15, 15 \sqrt{5}, 75}$ ${3,3sqrt5,15,15sqrt5,75}$

a GP is generated by multiplying the previous term by the common ration.

Starting with the first term given.

$a_{1} = 3$ $a_1=3$

$a_{2} = 3 \times \sqrt{5} = 3 \sqrt{5}$ $a_2=3xxsqrt5=3sqrt5$

$a_{3} = 3 \sqrt{5} \times \sqrt{5} = 3 \times 5 = 15$ $a_3=3sqrt5xxsqrt5=3xx5=15$

$a_{4} = 15 \times \sqrt{5} = 15 \sqrt{5}$ $a_4=15xxsqrt5=15sqrt5$

$a_{5} = 15 \sqrt{5} \times \sqrt{5} = 15 \times 5 = 75$ $a_5=15sqrt5xxsqrt5=15xx5=75$

How do you write the first five terms of the geometric sequence a_1=3, r=sqrt5a1=3,r=√5a_1=3, r=sqrt5?