# How do you write the first five terms of the sequence #a_n=2-1/3^n#?

##### 2 Answers

Feb 18, 2017

#### Explanation:

First term would be for n=1, thus

2nd term would be for n=2.thus

3rd term would be for n=3, thus

4th term would be for n=4, thus

5th term would be for n=5, thus

Feb 18, 2017

#### Explanation:

Let

Then

#3, 9, 27, 81, 243#

Let

Then

#5, 17, 53, 161, 485#

Then:

#a_n = 2-1/3^n = (2*3^n-1)/3^n = b_n/c_n#

So

#5/3, 17/9, 53/27, 161/81, 485/243#