# How do you write the first five terms of the sequence #a_n=n(n^2-6)#?

##### 2 Answers

#### Explanation:

Just plug in

We know that the

So,

Hence, the first five terms of the sequence

#### Explanation:

#"substitute corresponding value for n into "a_n=n(n^2-6)#

#a_n=n(n^2-6)=n^3-6n#

#rArra_(color(red)(1))=(color(red)(1))^3-(6xxcolor(red)(1))=1-6=-5#

#rArra_(color(red)(2))=(color(red)(2))^3-(6xxcolor(red)(2))=8-12=-4#

#rArra_(color(red)(3))=(color(red)(3))^3-(6xxcolor(red)(3))=27-18=9#

#rArra_(color(red)(4))=(color(red)(4))^3-(6xxcolor(red)(4))=64-24=40#

#rArra_(color(red)(5))=(color(red)(5))^3-(6xxcolor(red)(5))=125-30=95#