# How do you write the first six terms of an arithmetic sequence if the first term a1, is -4, and the common difference, d, is 10?

Jul 17, 2016

${a}_{n} = 10 n - 14$.

Taking, $n = 1 , 2 , \ldots \ldots \ldots . . , 6$ we get the answers., e.g., ${a}_{1} = - 4$

#### Explanation:

The formula for the general ${n}^{t h}$ term $= {a}_{n}$ of an A.P. with ${a}_{1}$ as its

first term, and common diff. $d \ne 0$ is given by,

${a}_{n} = {a}_{1} + \left(n - 1\right) d$.

$\therefore {a}_{n} = - 4 + 10 \left(n - 1\right) = 10 n - 14$

Taking, $n = 1 , 2 , \ldots \ldots \ldots . . , 6$ we get the answers., e.g., ${a}_{1} = - 4$