How do you write the first six terms of the sequence a_n=3-n?

Apr 4, 2017

2, 1, 0, -1, -2, -3

Explanation:

Since this is an arithmetic sequence which is defined on natural numbers the first six terms can simply be obtained by substituting n with 1, 2, 3, 4, 5, 6.

$i . e .$

${a}_{1} = 3 - 1 = 2$
${a}_{2} = 3 - 2 = 1$
${a}_{3} = 3 - 3 = 0$
${a}_{4} = 3 - 4 = - 1$
${a}_{5} = 3 - 5 = - 2$
${a}_{6} = 3 - 6 = - 3$