How do you write the first six terms of the sequence #a_n=3n+1#?

1 Answer
Aug 7, 2016

#4, 7, 10, 13, 16, 19#

Explanation:

#n# indicates the number of terms, or a term in a particular position.

#n# a;ways starts from 1.

So we need to use #n = 1, n = 2, n=3# etc

#a_1 = 3(1)+1 = 4#
#a_2 = 3(2) +1= 7#
#a_3 = 3(3)+1 = 10#

But by this term we can see that each term is 3 more than the previous :

#13, 16, 19#

For an AP, the coefficient of the #n# term also indicates #d#.