How do you write the first six terms of the sequence #a_n=6-n#?

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Answer 1 · 2016-12-12T14:55:07

Suppose that #n# starts from the value zero hence

#n=0,1,2,3,...#

Just replace that value of #n# in the formula #a_n=6-n# hence

for #n=0# we have #a_0=6-0=6#

for #n=1# we have #a_1=6-1=5#

for #n=2# we have #a_2=6-2=4#

for #n=3# we have #a_3=6-3=3#

for #n=4# we have #a_4=6-4=2#

for #n=5# we have #a_5=6-5=1#