# How do you write the first six terms of the sequence a_n=(n+2)/(2n)?

Sep 17, 2016

$\frac{3}{2}$, $1$, $\frac{5}{6}$, $\frac{3}{4}$,$\frac{7}{10}$, $\frac{2}{3}$

#### Explanation:

${a}_{n} = \frac{n + 2}{2 n}$

Plug in n=1, n=2,....n=6

${a}_{1} = \frac{1 + 2}{2 \cdot 1} = \frac{3}{2}$

${a}_{2} = \frac{2 + 2}{2 \cdot 2} = 1$

${a}_{3} = \frac{3 + 2}{2 \cdot 3} = \frac{5}{6}$

${a}_{4} = \frac{4 + 2}{2 \cdot 4} = \frac{3}{4}$

${a}_{5} = \frac{5 + 2}{2 \cdot 5} = \frac{7}{10}$

${a}_{6} = \frac{6 + 2}{2 \cdot 6} = \frac{2}{3}$