How do you write the following expression in standard form #i/(3-2i)+(2i)/(3+8i)#?

1 Answer
Aug 19, 2016

Answer:

I found: #62/949+297/949i#

Explanation:

Here we need to divide BUT the division is a little bit more difficult because we have complex numbers in the two denominators. To solve this we try to change the denominators into REAL numbers (eliminating the #i#). This is possible by multiplying AND dividing (red circle) by the complex conjugate of the denominator of each fraction:

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