How do you write the following expression in standard form #i/(3-2i)+(2i)/(3+8i)#?

1 Answer
Gió
Aug 19, 2016

I found: #62/949+297/949i#

Explanation:

Here we need to divide BUT the division is a little bit more difficult because we have complex numbers in the two denominators. To solve this we try to change the denominators into REAL numbers (eliminating the #i#). This is possible by multiplying AND dividing (red circle) by the complex conjugate of the denominator of each fraction:

enter image source here

Related questions
See all questions in Division of Complex Numbers
Impact of this question
4782 views around the world
You can reuse this answer
Creative Commons License