How do you write the following quotient in standard form #1/(4-5i)^2#?
1 Answer
Nov 13, 2017
Explanation:
#"expand the denominator using FOIL method"#
#•color(white)(x)i^2=(sqrt(-1))^2=-1#
#rArr(4-5i)^2=16-40i+25i^2=-9-40i#
#rArr1/(4-5i)^2=1/(-9-40i)#
#"to rationalise the denominator multiply "#
#"numerator/denominator"#
#"by the "color(blue)"conjugate " "of "-9-40i#
#"the conjugate of "-9-40i" is "-9color(red)(+)40i#
#rArr(-9+40i)/((-9-40i)(-9+40i))#
#=(-9+40i)/1681#
#=-9/1681+40/1681ilarrcolor(blue)"in standard form"#