How do you write the following quotient in standard form 6/i? Precalculus Complex Numbers in Trigonometric Form Division of Complex Numbers 1 Answer Ratnaker Mehta Sep 18, 2016 -6i. Explanation: 6/i=6/ixxi/i=(6i)/i^2=(6i)/-1=-6i. Answer link Related questions How do I graphically divide complex numbers? How do I divide complex numbers in standard form? How do I find the quotient of two complex numbers in polar form? How do I find the quotient (-5+i)/(-7+i)? How do I find the quotient of two complex numbers in standard form? What is the complex conjugate of a complex number? How do I find the complex conjugate of 12/(5i)? How do I rationalize the denominator of a complex quotient? How do I divide 6(cos^circ 60+i\ sin60^circ) by 3(cos^circ 90+i\ sin90^circ)? How do you write (-2i) / (4-2i) in the "a+bi" form? See all questions in Division of Complex Numbers Impact of this question 3367 views around the world You can reuse this answer Creative Commons License