How do you write the function in standard form #y=2(x-1)(x-6)#?

1 Answer
May 24, 2018

#y=2x^2-14x+12#

Explanation:

Standard form of a quadratic takes the shape #ax^2+bx+c=0#. This usually comes about from an expansion of the expression #(alphax+beta)(gammax+delta)#, using the distributive property such that #(a+b)(c+d)=ac+ad+bc+bd#.

Using these rules, we now expand the expression
#y=(2)(x-1)(x-6)# by first multiplying the first two brackets, to get
#y=( 2*x + 2*-1)(x-6) = (2x-2)(x-6)#. Next we expand the last two brackets, to get
#y=2x*x+2x*(-6)+(-2)* x+(-2)*(-6)# #= 2x^2-12x-2x+12#
Lastly we simplify by grouping like terms, to get
#y=2x^2-14x+12#, the answer.

I hope that helped!