# How do you write the function in standard form y=(5x+8)(4x+1)?

Apr 17, 2017

See the entire solution process below.

#### Explanation:

To write this equation in standard form you must multiply the two terms on the right side of the equation. To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

$y = \left(\textcolor{red}{5 x} + \textcolor{red}{8}\right) \left(\textcolor{b l u e}{4 x} + \textcolor{b l u e}{1}\right)$ becomes:

$y = \left(\textcolor{red}{5 x} \times \textcolor{b l u e}{4 x}\right) + \left(\textcolor{red}{5 x} \times \textcolor{b l u e}{1}\right) + \left(\textcolor{red}{8} \times \textcolor{b l u e}{4 x}\right) + \left(\textcolor{red}{8} \times \textcolor{b l u e}{1}\right)$

$y = 20 {x}^{2} + 5 x + 32 x + 8$

We can now combine like terms:

$y = 20 {x}^{2} + \left(5 + 32\right) x + 8$

$y = 20 {x}^{2} + 37 x + 8$