Question

How do you write the function in standard form `y=-7/3(x+6)(x+3)`?

Answer 1

Is standard form y = `ax^2+bx+c` for you, or is
it y = `a(x-h)^2+k`? I call the second equation "vertex" form.

Explanation:

So, take y = `-7/3(x+6)(x+3)` and expand by multiplication:

y = `-7/3(x^2+9x+18)`

First, help with fractions: `-7/3*9=-63/3=-21` and `-7/3*18=-7*6 =-42`.

Distribute: y = `-7/3x^2-21x+(-42)`. This is what I call standard form.