How do you write the function in standard form $y=-7/3(x+6)(x+3)$ ?

Question

2179 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-08-24T00:29:29

Is standard form y = $ax^2+bx+c$ for you, or is
it y = $a(x-h)^2+k$ ? I call the second equation "vertex" form.

So, take y = $-7/3(x+6)(x+3)$ and expand by multiplication:

y = $-7/3(x^2+9x+18)$

First, help with fractions: $-7/3*9=-63/3=-21$ and $-7/3*18=-7*6 =-42$ .

Distribute: y = $-7/3x^2-21x+(-42)$ . This is what I call standard form.

How do you write the function in standard form y=-7/3(x+6)(x+3)y=-7/3(x+6)(x+3)?