How do you write the general form given a circle that passes through the given (x-2)^2 + (y+1)^2 = 9?

1 Answer
Jim G.
Apr 1, 2016

x^2+y^2-4x+2y-4 = 0

Explanation:

The general form of the equation of a circle is.

x^2 + y^2 + 2gx + 2fy + c = 0

To write the given equation in this form , requires expanding the brackets and rearranging into the general form.

(x-2)^2 = x^2-4x+4" and " (y+1)^2 = y^2+2y+1

hence: x^2-4x+4+y^2+2y+1 = 9

rArr x^2+y^2+4x+2y-4 = 0 " is in general form "

Related questions
See all questions in General Form of the Equation
Impact of this question
1973 views around the world
You can reuse this answer
Creative Commons License