How do you write the nth term rule for the arithmetic sequence with d=4 and $a_{14} = 46$ $a_14=46$ ?

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How do you write the nth term rule for the arithmetic sequence with d=4 and $a_{14} = 46$ $a_14=46$ ?

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Answer 1 · 2016-08-13T21:24:16

$a_{n} = 4 n - 10$ $a_n = 4n- 10$

Explanation:

The nth term rule is $a_{n} = a_{1} + (n - 1) d$ $a_n = a_1 + (n-1)d$
To write the nth term rule we need to know both d and a.
We have $d = 4$ $d = 4$ and the value of a_14#

$a_{14} = a + (14 - 1) 4 = 46$ $a_14 = a + (14-1)4 = 46$

$a + 13 \times 4 = 46$ $a +13xx4 = 46$

$a = - 6$ $a =-6$

$a_{n} = - 6 + (n - 1) 4$ $a_n = -6 + (n-1)4$

$a_{n} = - 6 + 4 n - 4$ $a_n = -6 +4n -4$

$a_{n} = 4 n - 10$ $a_n = 4n- 10$

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How do you write the nth term rule for the arithmetic sequence with d=4 and $a_{14} = 46$ $a_14=46$ ?

1 Answer

Explanation:

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Science

Math

Humanities

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How do you write the nth term rule for the arithmetic sequence with d=4 and a14=46a_14=46?

1 Answer

Explanation:

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Impact of this question

How do you write the nth term rule for the arithmetic sequence with d=4 and $a_{14} = 46$ $a_14=46$ ?