# How do you write the nth term rule for the sequence 11/2,25/6,17/6,3/2,1/6,...?

${a}_{0} = \frac{33}{6} = \frac{11}{2}$, ${a}_{k} = \frac{33 - 8 k}{6}$
$\frac{33}{6} , \frac{25}{6} , \frac{17}{6} , \frac{9}{6} , \frac{1}{6} , - \frac{7}{6} , - \frac{15}{6} \cdots$
Calling ${a}_{0} = \frac{33}{6} = \frac{11}{2}$ then ${a}_{k} = \frac{33 - 8 k}{6}$