How do you write the partial fraction decomposition of the rational expression #(x - 16) / (x^2 + x - 2)#?

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Answer 1 · 2015-12-13T22:30:44

#6/(x+2)-5/(x-1)#

The expression equals #(x-16)/((x+2)(x-1))#.

#(x-16)/((x+2)(x-1))=A/(x+2)+B/(x-1)#

#x-16=A(x-1)+B(x+2)#

IF #x=1#:

#-15=3B#
#B=-5#

IF #x=-2#:

#-18=-3A#
#A=6#

#(x-16)/(x^2+x-2)=6/(x+2)-5/(x-1)#