How do you write the prime factorization of 48?

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Answer 1 · 2018-03-16T07:13:47

#48 = 2xx2xx2xx2xx3 = 2^4xx3#

Expand #48# into the product of all its prime factors:

#48 = 8xx6#

#48 = 2xx4xx2xx3#

#48 = 2xx2xx2xx2xx3#

(It does not matter which factors you start with, you will always get to the same answer.)

Or Use division, and divide by only prime factors.

#2|ul48#
#2|ul24#
#2|ul12#
#2|ul6#
#3|ul3#
#" "|ul1" "larr# divide till you get to #1#

#:. 48 = 2xx2xx2xx2xx3 = 2^4xx3#