# How do you write the quadratic equation in standard form x^2 - 12 + 4x = (x - 2)^2 + 2?

Oct 22, 2016

you have to expand the left hand side and rearrange to have 0 on one side.

#### Explanation:

so first expand ${\left(x - 2\right)}^{2} + 2$ to ${x}^{2} - 4 x + 4$
leaving us with
${x}^{2} + 4 x - 12 = {x}^{2} - 4 x + 4$
$8 x - 18 = 0$

which is in standard form.