How do you write the repeating decimal 0.73 where 73 is repeated as a fraction? Precalculus Series Infinite Series 1 Answer Annie · EZ as pi Oct 16, 2016 Answer: #73/99# Explanation: #N= 0.737373... # ( equation 1) Multiply both sides by 100 because 2 digits recur #100N=73.737373.. #( equation 2) If we subtract equation 1 from equation 2 we get #99N= 73# So N =#(73)/(99)# Related questions What are some examples of infinite series? Can an infinite series have a sum? What are some examples of convergent series? What are common mistakes students make with infinite series? How do I use an infinite series to find an approximation for pi? How do I find the sum of the infinite series 1 + #1/5# + #1/25# +... ? How do I find the sum of the infinite series #1/2# + 1 + 2 + 4 +... ? What are some examples of divergent series? How do you find the sum of the infinite geometric series 1/2+1/4+1/8+1/16..? How do you find the sum of the infinite geometric series 3-1+1/3...? See all questions in Infinite Series Impact of this question 2679 views around the world You can reuse this answer Creative Commons License