How do you write the solution set of #6+4(x+4) >= x + 7(x+1) + 8#?

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Answer 1 · 2017-03-19T11:02:43

#"Answer " 7/4>=x#

#6+4(x+4)>=x+7(x+1)+8#

#"Rearrange the inequality"#

#6+4x+16>=x+7x+7+8#

#4x+22>=8x+15#

#22-15>=8x-4x#

#7>=4x#

#7/4>=x#