# How do you write the standard form of a line given x-intercept=3 , y-intercept=2?

##### 1 Answer

Dec 14, 2017

#### Explanation:

#"the equation of a line in "color(blue)"standard form"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(Ax+By=C)color(white)(2/2)|)))#

#"where A is a positive integer and B, C are integers"#

#"the equation of a line in "color(blue)"slope-intercept form"# is.

#•color(white)(x)y=mx+b#

#"where m is the slope and b the y-intercept"#

#"to calculate m use the "color(blue)"gradient formula"#

#color(red)(bar(ul(|color(white)(2/2)color(black)(m=(y_2-y_1)/(x_2-x_1))color(white)(2/2)|)))#

#"let "(x_1,y_1)=(3,0)" and "(x_2,y_2)=(0,2)#

#rArrm=(2-0)/(0-3)=-2/3#

#rArry=-2/3x+2larrcolor(red)"in slope-intercept form"#

#"multiply through by 3"#

#rArr3y=-2x+6#

#rArr2x+3y=6larrcolor(red)"in standard form"#