# How do you write the standard from of the equation of the circle given center (-2,8) and radius 12?

Jun 3, 2016

${\left(x + 2\right)}^{2} + {\left(y - 8\right)}^{2} = 144$

#### Explanation:

The standard form of the equation of a circle is.

$\textcolor{red}{| \overline{\underline{\textcolor{w h i t e}{\frac{a}{a}} \textcolor{b l a c k}{{\left(x - a\right)}^{2} + {\left(y - b\right)}^{2} = {r}^{2}} \textcolor{w h i t e}{\frac{a}{a}} |}}}$
where (a ,b) are the coordinates of the centre and r, the radius.

here a = -2 , b = 8 and r = 12

$\Rightarrow {\left(x + 2\right)}^{2} + {\left(y - 8\right)}^{2} = 144 \text{ is equation of circle}$