How do you write the standard from of the equation of the circle given center (2, 3) and radius 4?
The standard form of the equation of a circle is.
where (a ,b) are the coordinates of the centre and r, the radius.
Here the centre = (2 ,3) hence a = 2 , b=3 and r = 4
substitute these values into the standard form of the equation.
#rArr(x-2)^2+(y-3)^2=16" is the equation of the circle"#