How do you write the standard from of the equation of the circle given center (-3, -5) and radius 4?

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Answer 1 · 2016-10-08T15:07:51

#(x - -3)² + (y - -5)² = 4²#

#(x - h)² + (y - k)² = r²#

where #(h, k)# is the center point, and #r# is the radius.

Substituting the given values into the equation:

#(x - -3)² + (y - -5)² = 4²#

You can change into this form:

#(x +3)² + (y +5)² = 16#

but I do not recommend it, because it makes is more difficult for someone to identify the center and the radius.