# How do you write the standard from of the equation of the circle given Center (3, 4) and radius 6?

Oct 18, 2016

${\left(x - 3\right)}^{2} + {\left(y - 4\right)}^{2} = {6}^{2}$
${\left(x - h\right)}^{2} {\left(y - k\right)}^{2} = {r}^{2}$
where $\left(h , k\right)$ is the center point and $r$ is the radius.