How do you write the standard from of the equation of the circle given center (5,-3) and radius 7?
The standard form of the equation of a circle is
where (a ,b) are the coordinates of the centre and r, the radius.
Here centre = (5 ,-3) hence a = 5 , b = -3 and r = 7
Substitute these values into the standard equation.
#rArr(x-5)^2+(y+3)^2=49" is the equation"#