# How do you write the trigonometric form of 6i?

Feb 13, 2017

$= 6 {e}^{i \frac{\pi}{2}}$
$6 i = 0 + 6 i = 6 \left(\cos \left(\frac{\pi}{2}\right) + i \sin \left(\frac{\pi}{2}\right)\right) = 6 {e}^{i \frac{\pi}{2}}$