# How do you write x = 1/3 y – 2/3  in standard form?

Apr 15, 2018

See a solution process below..

#### Explanation:

The standard form formula goes like this;

$A x + B x = C$

Where;

$A , B \mathmr{and} C$ are coefficients..

$x = \frac{1}{3} y - \frac{2}{3}$

First, multiply through by their LCM, in this case is $3$

$3 \left(x\right) = 3 \left(\frac{1}{3} y\right) - 3 \left(\frac{2}{3}\right)$

$3 x = 3 y - 2$

$3 x - 3 y = - 2 , \text{is in standard form}$