# How do you write (x-17.09)^2+(y-1.53)^2=1.03^2 into the general form?

Oct 13, 2016

This is the equation of a circle that is offset such that the centre is at

$\left(x , y\right) \to \left(17.09 , 1.53\right)$ and it has a radius of length $1.03$

This basically is already in general form for a circle.

#### Explanation:

Standard form is ${\left(x - h\right)}^{2} + {\left(y - k\right)}^{2} = {r}^{2}$

Where $r$ is the radius and $\left(h , k\right)$ is the centre.