# How do you write x+2 in standard form?

$x + 2$ is already in standard form.
For example, $2 + 6 {x}^{2} {y}^{2} - 3 {x}^{3}$ would be written as:
$6 {x}^{2} {y}^{2} - 3 {x}^{3} + 2$
The order of the first term is $2 + 2 = 4$, the next $3$ and the order of the constant term is $0$.