How do you write $(x^2 + x + 2) + (3x^2 - 2x + 10)$ in standard form?

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Answer 1 · 2016-05-31T05:41:40

$= 4*x²-x+12$

$= 4*x²-x+12$

Answer 2 · 2016-05-31T11:14:30

$" "4x^2-x+12$

As there is a + between the brackets so multiply the contents of the 2nd bracket by +1 giving:

$" "x^2+x+2" "+" "3x^2-2x+10$

Collecting like terms

$" "( x^2+3x^2)+(x-2x)+(2+10)$
The purpose of the above brackets is to make things clearer about what is happening. They serve no other purpose.

$" "4x^2-x+12$

'.................................
Note that $+(x-2x)$ is the same as $+(-x)$
where $+" and "- " give us "-$

so $+(-x)=-x$
'.............................................................

How do you write (x^2 + x + 2) + (3x^2 - 2x + 10)(x^2 + x + 2) + (3x^2 - 2x + 10) in standard form?