# How do you write (x-3)(x+2)(x+5) in standard form?

$\left(x - 3\right) \left(x + 2\right) \left(x + 5\right)$
$= \left({x}^{2} + 2 x - 3 x - 6\right) \left(x + 5\right)$
$= \left({x}^{2} - x - 6\right) \left(x + 5\right)$
$= {x}^{3} + 5 {x}^{2} - {x}^{2} - 5 x - 6 x - 30$
$= {x}^{3} + 4 {x}^{2} - 11 x - 30$