How do you write $y= -1 1/4x-3 1/4$ in standard form?

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Answer 1 · 2015-05-14T23:19:51

The given equation is standard form is $5x+4y=-13$ .

Standard form for a linear equation is Ax+By=C.

$y=-1(1)/(4)x-3(1)/(4)$

Convert fractions to improper form.

$y=(-5x)/4-13/4=(-5x-13)/4$

Multiply both sides by $4$ .

$4*y=(-5x-13)/cancel4*cancel4$ =

$4y=-5x-13$

Subtract $5x$ from both sides.

$5x+4y=-13$

How do you write y= -1 1/4x-3 1/4y= -1 1/4x-3 1/4 in standard form?