How do you write #y= -1 1/4x-3 1/4# in standard form?

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Answer 1 · 2015-05-14T23:19:51

The given equation is standard form is #5x+4y=-13# .

Standard form for a linear equation is Ax+By=C.

#y=-1(1)/(4)x-3(1)/(4)#

Convert fractions to improper form.

#y=(-5x)/4-13/4=(-5x-13)/4#

Multiply both sides by #4#.

#4*y=(-5x-13)/cancel4*cancel4# =

#4y=-5x-13#

Subtract #5x# from both sides.

#5x+4y=-13#