How do you write $y - 2 = \frac{1}{7} x$ $y - 2=1/7x$ in standard form?

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How do you write $y - 2 = \frac{1}{7} x$ $y - 2=1/7x$ in standard form?

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Answer 1 · 2015-09-02T21:20:42

$y = \frac{1}{7} x + 2$ $y=1/7 x +2$

Explanation:

It's almost already in standard form: you obtain the standard form when you write your equality as $y = f (x)$ $y=f(x)$ , for a certain $f (x)$ $f(x)$ .

If we add $2$ $2$ to both sides, we isolate the $y$ $y$ term, since we get

$y - 2 + 2 = \frac{1}{7} x + 2$ $y-2+2 = 1/7x +2$

and simplifying

$y = \frac{1}{7} x + 2$ $y=1/7 x +2$

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How do you write $y - 2 = \frac{1}{7} x$ $y - 2=1/7x$ in standard form?

1 Answer

Explanation:

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How do you write $y - 2 = \frac{1}{7} x$ $y - 2=1/7x$ in standard form?