How do you write #y-2/3 = -2( x-1/4 )# in standard form?

1 Answer
Sep 18, 2015

Answer:

# y = -2x + frac(7)(6) #

Explanation:

#y-frac(2)(3) = -2(x-frac(1)(4))#
so, after opening the parentheses, we get
#y-frac(2)(3) = -2x + frac(2)(4)#
which simplifies to
#y-frac(2)(3) = -2x + frac(1)(2)#
and moving #-frac(2)(3)# on the other side of the equality
#y = -2x + frac(1)(2)+frac(2)(3)#
then performing the fraction calculation
# y = -2x + frac(3)(6)+frac(4)(6)#
which gives
# y = -2x + frac(7)(6) #