How do you write #y + 2 = 4(x+2)# in standard form?

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Answer 1 · 2015-09-19T01:15:29

#y=4x+6#

It is a straight line equation.
#y+2=4(x+2)#
#y+2=4x+8#
#y=4x+8-2#
#y=4x+6#

Answer 2 · 2015-09-20T20:30:46

#y = 4x+6#

Expand the right side and isolate #y#
#y + 2 = 4(x + 2)#
#y + 2 = 4x + 8#
#y + 2 - 2= 4x + 8 - 2#
#y = 4x + 6#

graph{y = 4x + 6 [-20,20, -15, 15]}