# How do you write #y^2+4x+8y+12=0# in standard form and then graph the parabola?

##### 1 Answer

Oct 22, 2017

Standard form of parabola =

graph{-(1/4)(x^2+8x+12) [-10, 10, -5, 5]}

Axis of symmetry drawn parallel to Y-axis. May rotate it by 90^0 to make it parallel to X-axis.

#### Explanation:

Standard form of parabola is

Focus = ((h + p), k) = (0, -4) and Directrix x = h - p = 1 - (-1) = 2#