# How do you write y = 2(x + 4)^2 - 21 in standard form?

Standard form relates to writing a function such as yours as $a {x}^{n} + b {x}^{n - 1} + \ldots + a ' {y}^{n} + b ' {y}^{n - 1} + \ldots$constant
$y = 2 \left({x}^{2} + 8 x + 16\right) - 21$
$y = 2 {x}^{2} + 16 x + 32 - 21$
$y = 2 {x}^{2} + 16 x + 11$
$2 {x}^{2} + 16 x - y + 11 = 0$