How do you write #y = 3/4x + 1/2# in standard form?
1 Answer
Mar 3, 2017
Explanation:
The equation of a line in
#color(blue)"standard form"# is.
#color(red)(bar(ul(|color(white)(2/2)color(black)(Ax+By=C)color(white)(2/2)|)))#
where A is a positive integer and B, C are integers.
#y=3/4x+1/2#
#"subtract "3/4x" from both sides"#
#y-3/4x=cancel(3/4x)cancel(-3/4x)+1/2#
#rArr-3/4x+y=1/2#
#"multiply ALL terms by "-4#
#rArr3x-4y=-2larrcolor(red)" in standard form"#
