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How do you write $y = - 3 (x - 3) (x + 2)$ $y=-3(x-3)(x+2)$ in standard form?

1 Answer

Jul 13, 2015

$y = - 3 x^{2} + 3 x + 18$ $y = -3x^2+3x+18$

Explanation:

Standard form for a quadratic (in variables $x$ $x$ and $y$ $y$ ) is
$XXXX$ $color(white)("XXXX")$ $y = a x^{2} + b x + c$ $y = ax^2+bx+c$

$y = - 3 (x - 3) (x + 2)$ $y=-3(x-3)(x+2)$
can be converted into "standard form" by multiplying the factors on the right side:

$y = (- 3) (x^{2} - x - 6)$ $y = (-3)(x^2-x-6)$

$y = - 3 x^{2} + 3 x + 18$ $y = -3x^2+3x+18$

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