How do you write $y=4(x+3/2)(3/4x+1/4)$ in standard form?

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Answer 1 · 2017-05-29T07:20:56

$3x^2+11/2x+3/2=0$

First I would use the distributive law to expand the brackets, but for now ignore the 4.

So it becomes:
$4(3/4x^2+1/4x+9/8x+3/8)$

Then simplify everything in he brackets to become:
$4(3/4x^2+11/8x+3/8)$

Then times all 3 terms by 4, so it becomes:
$3x^2+11/2x+3/2$

Then simply add $=0$ to finish in standard form.
$3x^2+11/2x+3/2=0$

How do you write y=4(x+3/2)(3/4x+1/4)y=4(x+3/2)(3/4x+1/4) in standard form?