# How do you write y=4(x+3/2)(3/4x+1/4) in standard form?

May 29, 2017

$3 {x}^{2} + \frac{11}{2} x + \frac{3}{2} = 0$

#### Explanation:

First I would use the distributive law to expand the brackets, but for now ignore the 4.

So it becomes:
$4 \left(\frac{3}{4} {x}^{2} + \frac{1}{4} x + \frac{9}{8} x + \frac{3}{8}\right)$

Then simplify everything in he brackets to become:
$4 \left(\frac{3}{4} {x}^{2} + \frac{11}{8} x + \frac{3}{8}\right)$

Then times all 3 terms by 4, so it becomes:
$3 {x}^{2} + \frac{11}{2} x + \frac{3}{2}$

Then simply add $= 0$ to finish in standard form.
$3 {x}^{2} + \frac{11}{2} x + \frac{3}{2} = 0$